So what is there to protest at this point, exactly? That BART is determined to exterminate, discriminate against minorities? That the officer has been cleared of wrongdoing? The BART cops were reacting to a brawl among thugs at two am, there was some kind of incident and one of the thugs died, and everyone is sorry it happened. Do these protesters want someone swinging from a telephone pole, or what? An investigation is going on, the truth will emerge. The problem is, when a black is violently killed in a way other than the usual method, conspiracy and other grievances are vented, it acts as a lightning rod that often sets the stage for more violence, riots, and excesses, which is then ascribed to the uncaring and racist society at large. This post might hurt some feelings, but it's not "abuse".

(From an old ass thread)

Exact same starting hand 3 times in a row 1758276.

As for the any Ace starting hand 8 times in a row�

Let�s start by pointing out that there are 1326 possible starting hands in Texas Hold Em. If we know how this is figured then we can figure out exactly how many hands one card is involved in out of those 1326.

(52x51)/(1x2)=1326

You have to know this to compare what percent of hands the aces is involved in.

Ok so when you take away any 4 cards the number of possible hands is

(48x47)/(1x2)=1128

So now we get

1128/1326= .8506, 1-.8506=.1494 meaning that you will be dealt an ace 14.94% of the time.

This converts to 6.7/1.

Simple explanation that a simple one can explain to himself

1326-1128=198 That means any card, an ace king jack queen etc. with the 12 other types of cards in the deck can combine for 198 combinations with itself.

Example:
Ad: 2c 2h 2s 2d
Ah: 2c 2h 2s 2d
As: 2c 2h 2s 2d
Ac: 2c 2h 2s 2d

That equals 16 combos per card which x12=192 Then add the number of different ways you can get pocket Aces.

Ad c h s
Ac h s
As h

6 ways

198

So out of the 1326 combinations when trying to draw for a hand involving any one specific card its 1326/198 which equals 6.7.

Once you catch the initial Ax the odds of getting any Ax 7 more times in a row is overcoming a 5.7 to 1 shot 7 times. So this would be �

5.7^7 (5.7x1x5.7x5.7�. . .)

Which equals
195489.75 to 1



(There are several ways to get this answer; this one seems the easiest to explain. I did it like this for a reason.)